How Do You Find The Vertical Asymptotes Of The Function Y X 2 1 3x 2x 2

The vertical asymptotes of ##y=(x^2+1)/(3x-2x^2)## are##x=0## and ##x=3/2##.

To find the vertical asymptotes we set the denominator equal to zero.

##3x-2x^2=x(3-2x)=0rArrx=0 or x=3/2##

Look at the graph below.

Sometimes, the denominator is equal to zero at the same x-value that makes the numerator zero. This will produce a instead of a vertical asymptote.